Question

The length of a rectangle is 27 m longer than its breadth . If the perimeter of a rectangle is 110 m . Find its area

Answer 1

Step-by-step explanation:

LET THE BREADTH BE x.

AND LENGTH BE 27+x

P=2(l+b)

110=2(27+x+x)

110/2=27+2x

55=27+2x

55-27=2x

28=2x

x=28/2

x=14

LENGTH=14+27

=41m

BREADTH=14m

AREA=L×B

AREA=41×14

AREA OF RECTANGLE=574m^2

HOPE IT HELPS U

Answer 2

Answer:

Step-by-step explanation:

let us examine the breadth of rectangle be x

then,length would be=x+27m

perimeter of rectangle=2[l+b]

      110m                     =     2{[x+27m]+x}

      110/2                =         2x+27

       55m                  =      2x+27m

       55m-27m        =      2x

         28m              =       2x

          28/2            =       x

          14m              =      x

x+27 =    41m

area of rectangle       =l.b

                               =    41m *   14m

                               =574m[sq]

hope you understood  !!!!!!!