the length of a rectangle is 27 m longer than its breadth. if the perimeter of the rectangle is 110 m, then find its area
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Given
Length of rectangle is 27m longer than breadth
Perimeter = 110 m
To Find
Area of rectangle
Solution
Let the breadth of rectangle be x so the length will be x + 27
perimeter of rectangle = 2 ( length + breadth )
110 =2 ( x + x + 27 )
110 = 2 ( 2x + 27 )
110 = 4x + 54
4x = 110 - 54
4x = 56
x = 56/4
x = 14 m
so the breadth of rectangle is 14 cm
and the length is 41 m
Area of rectangle = breadth × length
= 14 × 41
= 574 m^2
so the area of rectangle is 574 m^2
Length of rectangle is 27m longer than breadth
Perimeter = 110 m
To Find
Area of rectangle
Solution
Let the breadth of rectangle be x so the length will be x + 27
perimeter of rectangle = 2 ( length + breadth )
110 =2 ( x + x + 27 )
110 = 2 ( 2x + 27 )
110 = 4x + 54
4x = 110 - 54
4x = 56
x = 56/4
x = 14 m
so the breadth of rectangle is 14 cm
and the length is 41 m
Area of rectangle = breadth × length
= 14 × 41
= 574 m^2
so the area of rectangle is 574 m^2
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