Question

The length of a rectangle is 27 m longer than its breadth. If the perimeter of the rectangle of the rectangle is 110m then Find its area​

Answer 1

Question :

• Length $\leadsto$ (b + 27)m
• Breadth $\leadsto$ x
• Perimeter $\leadsto$ 110m

To find :

• We have to find the Length , breadth and the Area of the rectangle

Solution :

$: \implies \sf 110m = 2 \times[(B + 27) + x ] \\ \\ \\ : \implies \sf \dfrac{ \cancel{110}}{ \cancel{2}} = 55m \\ \\ \\ : \implies \sf 55m = [(B + 27) + x] \\ \\ \\ : \implies \sf 55 - 27 = 28m \\ \\ \\ : \implies \sf 28m = (2 \purple\times x) \\ \\ \\ : \implies \sf \dfrac{ \cancel{28}}{ \cancel{2}} = 14m \\ \\ \\ { \underline{ \boxed{ \mathfrak{ \pink{Breadth \leadsto 14m}}}}} \\ \\ \\ \\ : \implies \sf Length \: = (B + 27) \\ \\ \\ : \implies \sf 14m + 27 \\ \\ \\ : \implies \sf { \underline{ \boxed{ \mathfrak{ \pink{ Length\leadsto 41m}}}}} \\ \\ \\ \therefore { \underline{ \sf{Now, \: we \: will \: find \: the \: area \: of \: rectangle :}}} \\ \\ \\ \;\boxed{\sf{\purple{Area_{\:(rectangle)} = Length \times Breadth}}} \\ \\ \\ : \implies \sf 14m \times 41m \\ \\ \\ : \implies { \underline{ \boxed{ \mathfrak{ \pink{Area \leadsto 247 {m}^{2} }}}}}$

•°• Hence, verified!

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