Question

The length of a rectangle is 27 m longer than its breath and if the perimeter of the rectangle is 110 find its area


itz Ananya​

Answer 1

To find : area of rectangle field.

Given :  length of a rectangle is 27 m longer than its breath and if the perimeter of the rectangle is 110 m.  

Solution :

• According to question we are given that  length of a rectangle is 27 m longer than its breath and its perimeter of the rectangle is 110 m. We have to find area of rectangle .  
• Let , breadth be $x$ m and length be $( x + 27 ) \ m$
• Perimeter = $2 (l + b )$  

      $110 = 2 (27 +x +x ) \\55 = 27 + 2x \\55-27 = 2x \\28 =2x \\x = 14$

• Now , breadth is $x = 14\ m$ and length is  $( x + 27 ) \ m = 14 + 27 = 41\ m$

• To find area we use following formula -

         Area of rectangle $= l\times b$

• Substituting the values we get,
• Area of rectangle = $41 \times 14$

                                      $= 574\ m^{2}$

Hence , area of rectangle is $574\ m^{2}$ .

Note : since the unit of perimeter was not given we assumed it to be meter as unit of length was given in meter .