Question

The length of a rectangle is 2cm less than twice it’s width. if the area is 84cm^2, find its dimensions

Answer 1

Answer:

w = 7, l = 12

Step-by-step explanation:

Let the width = w

Then length = 2w - 2

Area = Length x width = 84

w * (2w - 2) = 84

2$w^{2}$ - 2w - 84 = 0

$w^{2}$ - w - 42 = 0

Splitting the middle term, we get

$w^{2}$ - 7w + 6w - 42 = 0

w(w - 7) + 6(w - 7) =0

(w+6)(w-7) = 0

Therefore w = -6 (not possible) and w = 7

Therefore widhth = 7 and length = (2*7) - 2 = 12

Answer 2

Answer:

Length = 12 cm And Breadth = 7 cm

Step-by-step explanation:

HEY MATE YOUR ANSWER IS HERE^_^

let the breadth of rectangle is x then length equals 2x-2

84 = x(2x-2)

42 = x(x-1)

therefore x = 7

hence length = 12 cm and breadth = 7 cm

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