Math, asked by lsomu784, 21 days ago

The length of a rectangle is (2p + 5q) and its breadth is (3r - 4s) respectively. Find its area.​

Answers

Answered by aditrirastogi
0

Given,

The area of a rectangle = 2p(3q - 5) square unit and

The length of a rectangle (l) = 4p units

To find, the breadth of a rectangle (b) = ?

We know that,

The area of a rectangle = Length(l) × Breadth(b)

∴ 4p × b = 2p(3q - 5)

Answered by aftabahemad
0

In context to question asked,

We have to determine the area of the rectangle.

As per question,

it is given that,

Length of rectangle = (2p +5q)

Breadth of rectangle = (3r - 4s)

As we know that,

Area of rectangle will be length \times breadth

So, putting the value of length and breadth in above equation,

We will get,

Area = (2p+5q) (3r-4s)\\=>Area = 2p \times 3r -2p \times 4s +5q \times 3r -5q \times 4s\\=>Area = 6pr-8ps+15qr-20qs

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