the length of a rectangle is 3 cm more than twice its width. if the area of the rectangle is 65, find its length
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Solution:-
Given:-
- Area of Rectangle = 65cm²
- It's length is 3 cm more than twice its width.
To Find:-
- length = ?
Find:-
Let the width of the Rectangle be "x" cm.
Let the width of the Rectangle be "x" cm.=) Length = (2x + 3) cm
Now,
Area of Rectangle = Length × Breadth
=) 65 = x ( 2x + 3)
=) 65 = 2x² + 3x
=) 2x² + 3x - 65 = 0
=) 2x² + ( 13 - 10)x - 65 = 0
=) 2x² + 13x - 10x - 65 = 0
=) x ( 2x + 13 ) - 5 ( 2x + 13) = 0
=) ( 2x + 13) ( x - 5)
=) [ x = -13/2 ] and [ x = 5 ].
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