The length of a rectangle is 3 m longer than it’s width. If the perimeter of the rectangle is 34m. Find the area
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Let the breadth be 'x'.
Then it's length = x+3
Perimeter= 2(l+b)
=2(x+x+3)
=2(2x+3)
=4x+6=34(given)
4x=28
x=28/4=7m=breadth.
Length=x+3=10m
Area=7x10=70m²
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hey there
let the width = x m
therefore length = x + 3 m
and perimeter of rectangle = 2 ( length + width)
and perimeter = 34 m
so 34= 2(x + x +3)
34 = 4x + 6
4x = 28
x= 28/4
x = 7
now length = 7 + 3 =10 m
and width = 3 m.
area of rectangle = length × breadth
= 10 × 3 = 30 m^2
let the width = x m
therefore length = x + 3 m
and perimeter of rectangle = 2 ( length + width)
and perimeter = 34 m
so 34= 2(x + x +3)
34 = 4x + 6
4x = 28
x= 28/4
x = 7
now length = 7 + 3 =10 m
and width = 3 m.
area of rectangle = length × breadth
= 10 × 3 = 30 m^2
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