Question

the length of a rectangle is 3 more than its width . if the perimeter of the rectangle is 30 cm them find the length and breadth of rectangle.
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Answer 1

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➾Let width =’x’inches

➾Length=x+3

➾Perimeter=30 inches

⇒2(l+b)=30

⇒l+b=15

⇒x+3+x=15

⇒2x=12

⇒x=6

➣Therefore

➯breadth = 6 inches

➯length = x+3

➯6+3

➯9 inches

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Answer 2

Answer:

Let width =’x’inches

Let width =’x’inches➾Length=x+3

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15⇒2x=12

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15⇒2x=12⇒x=6

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15⇒2x=12⇒x=6➣Therefore

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15⇒2x=12⇒x=6➣Therefore➯breadth = 6 inches

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15⇒2x=12⇒x=6➣Therefore➯breadth = 6 inches➯length = x+3

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15⇒2x=12⇒x=6➣Therefore➯breadth = 6 inches➯length = x+3➯6+3

Let width =’x’inches➾Length=x+3➾Perimeter=30 inches⇒2(l+b)=30⇒l+b=15⇒x+3+x=15⇒2x=12⇒x=6➣Therefore➯breadth = 6 inches➯length = x+3➯6+3➯9 inches