the length of a rectangle is 3 times its width and the length of its diagonal is 6 square root 10 cm the perimeter of the rectangle is
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Let the width be x.
Then, length is 3x
Now,
Diagonal =√(l^2+b^2)
=√(9x^2 + x^2)
=√(10x^2) = x√10
But, diagonal = 6√10 cm
Hence, 6√10=x√10
Or, x=6 cm
Thus, perimeter = 3x+x = 4x = 4*6
= 24 cm
Then, length is 3x
Now,
Diagonal =√(l^2+b^2)
=√(9x^2 + x^2)
=√(10x^2) = x√10
But, diagonal = 6√10 cm
Hence, 6√10=x√10
Or, x=6 cm
Thus, perimeter = 3x+x = 4x = 4*6
= 24 cm
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