the length of a rectangle is 3 times its width and the length of its diagonal is 6 under root 10 centimetre the perimeter of a rectangle is
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Let the width of the rectangle be x
an length of the rectangle will be 3x
Given,
length of its diagonal is 6√10 cm
so by Pythagoras theorem
x^2 +(3x)^2 =(6√10)^2
x^2+9x^2= 360
10x^2=360
x^2=36
x=6
So breadth of the rectangle = 6cm
length of the rectangle= 3×6cm=18cm
So,
Perimeter of the rectangle = 2(6+18)cm
= 2×24cm=48cm
Hence perimeter of rectangle is 48 cm
Hope it helps
please mark as brainliest
an length of the rectangle will be 3x
Given,
length of its diagonal is 6√10 cm
so by Pythagoras theorem
x^2 +(3x)^2 =(6√10)^2
x^2+9x^2= 360
10x^2=360
x^2=36
x=6
So breadth of the rectangle = 6cm
length of the rectangle= 3×6cm=18cm
So,
Perimeter of the rectangle = 2(6+18)cm
= 2×24cm=48cm
Hence perimeter of rectangle is 48 cm
Hope it helps
please mark as brainliest
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