The length of a rectangle is 3 times its width and the length of its diagonal is 6√10 cm. Find its perimeter
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Let the breadth be 'x'm
Length is equal to three times breadth=3x
Perimeter=84m
2(l+b)=84m
2(3x+x)=84
2(4x)=84
4x=84/2
4x=42
x=42/2
x=10.5
Therefore length=3x=3(10.5)=31.5m
Breadth=x=10.5m
Length is equal to three times breadth=3x
Perimeter=84m
2(l+b)=84m
2(3x+x)=84
2(4x)=84
4x=84/2
4x=42
x=42/2
x=10.5
Therefore length=3x=3(10.5)=31.5m
Breadth=x=10.5m
priyajaiswal8780:
Sry but the question is to find the perimeter
Answered by
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hey here is your answer
Let the width be x.
Then, length is 3x
=>
Diagonal =√(l^2+b^2)
=√(9x^2 + x^2)
=√(10x^2) = x√10
But, diagonal = 6√10 cm
Hence, 6√10=x√10
x=6 cm
Thus, perimeter = 3x+x = 4x = 4*6 = 24 cm
therefore, perimeter is 24cm
Let the width be x.
Then, length is 3x
=>
Diagonal =√(l^2+b^2)
=√(9x^2 + x^2)
=√(10x^2) = x√10
But, diagonal = 6√10 cm
Hence, 6√10=x√10
x=6 cm
Thus, perimeter = 3x+x = 4x = 4*6 = 24 cm
therefore, perimeter is 24cm
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