Question

The length of a rectangle is 3 times its width. The perimeter of the rectangle is 48m.
What are the dimensions of the rectangle? Also find its area. pls tell the ans fast then only I will make you a brainlieast .

Answer 1

Answer:

ok her you go

Step-by-step explanation:

Area =108m  

2

=L×B; Perimeter =2(L+B)=48m

L×B=108⇒L=  

B

108

​  

⇒2[(  

B

108

​  

)+B]=48

=B  

2

+108=24B

After solving above equation

⇒B=18,6⇒L=6,18

Dimensions are 18,6 or 6,18

Answer 2

let the length of the rectangle is x________(1)

length is three times its width

therefore X=3y____________(2) (given)

(where y is the width)

perimeter of rectangle is =2(X+y)

48 =2(3y+y)

48=2(4y)

48 = y

8

y = 6 m

now if y= 6, then x=3y

X=3(6)

X= 18 m

area of rectangle is = X×y

= (18)(6)

= 108 m^2

hope this will help you.

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