the length of a rectangle is 30 cm and one of its diagonals measures 34 cm find the breadth perimeter and area of the rectangle
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Lenght=30
Diagonal=34
Breath=?
By Pythagoras theorem we can find breath
D^2=b^2+l^2
34^2=b^2+30^2
1156=b^2+900
1156-900=b^2
256=b^2
√256=b
16=b
Perimeter=2(l+b)
=2(16+30)
=2(46)
=92cm
Area=l*b
=16*30
=480cm^2
Thnxx:))
Diagonal=34
Breath=?
By Pythagoras theorem we can find breath
D^2=b^2+l^2
34^2=b^2+30^2
1156=b^2+900
1156-900=b^2
256=b^2
√256=b
16=b
Perimeter=2(l+b)
=2(16+30)
=2(46)
=92cm
Area=l*b
=16*30
=480cm^2
Thnxx:))
angleberry883:
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