Question

the length of a rectangle is 32m and the length of its digonal is 40m. Find its area​

Answer 1

Answer:

768

Step-by-step explanation:

40²-32²=576

√576=24

.........,.area =24x32=768

Answer 2

Let the above figure is a rectangle.

Given:

length = 32 m

diagonal = 40 m.

breadth = ? .

To find the breadh of rectangle,use Pythagoras theorem.

As we know that the adjacent interior angles of a rectangle are of 90 degree.

So , in triangle ABD,

$\large{h^{2}}$ = $\large{b^{2}}$ + $\large{p^{2}}$

$\large{40^{2}}$ = $\large{32^{2}}$ + $\large{p^{2}}$

$\large{p^{2}}$ = $\large{40^{2}}$ - $\large{32^{2}}$

$\large{p^{2}}$ = (40 + 32 ) (40 - 32 )

$\large{p^{2}}$ = 72 × 8

$\large{p^{2}}$ = 576

p = $\large\mathrm{\sqrt{ 576 }}$

p = 24 .

Here p becomes the breadth.

Now we have ,

length = 32 m

breadth = 24 m

So, area of rectangle = length × breadth .

area of rectangle = 32 × 24

area of rectangle = 768 metre square .