Question

The length of a rectangle is 3cm more than its breadth . perimeter is 50cm .
find the length and breadth of the rectangle​

Answer 1

Answer:

Then the length = x+3. Perimeter of rectangle is 50 cm. Formula to find perimeter = 2( l + b ) Therefore, 2 ( l + b ) =50 cm.

Answer 2

Given :

• Length of rectangle is 3 cm more than its breadth.

• ‎Perimeter is 50 cm

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To find :

• Length and breadth of the rectangle.

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Formula to be used :

$\bf\:\dag\: Perimeter~of~rectangle~=~2(l+b)$

where ,

• l denotes length of the rectangle
• b denotes breadth of the rectangle

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Assumption :

Let the breadth of the triangle be b.

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Solution :

According to the question ,

Length of a rectangle is 3 cm more than its breadth.

$\sf\therefore\:Length~=~b~+~3$

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Again ,

Perimeter of the rectangle is given as 50 cm.

Applying formula -

$\sf\longrightarrow\:2(l+b)~=~50$

Substituting the values -

$\sf\longrightarrow\:2[(b+3)+b]~=~50$

$\sf\longrightarrow\:2[b+3+b]~=~50$

$\sf\longrightarrow\:2[2b+3]~=~50$

$\sf\longrightarrow\:4b+6~=~50$

$\sf\longrightarrow\:4b~=~50-6$

$\sf\longrightarrow\:4b~=~44$

$\sf\longrightarrow\:b~=~\frac{44}{4}$

$\sf\longrightarrow\:b~=~\cancel{\frac{44}{4}}$

$\small{\underline{\boxed{\mathrm{\longrightarrow\:breadth~=~11~cm}}}}$

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Now calculating length of the rectangle by substituting the value of breadth -

$\sf\:Length~=~b~+~3$

$\sf\to\:Length~=~11~+~3$

$\small{\underline{\boxed{\mathrm{\longrightarrow\:length~=~14~cm}}}}$

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Verification :

Perimeter of the rectangle = 50 cm

$\sf\leadsto~2(l+b) ~=~50$

$\sf\leadsto~2(14+11) ~=~50$

$\sf\leadsto~2(25) ~=~50$

$\sf\leadsto~50 ~=~50$

Hence Verified !~

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Henceforth,

➻ Length of the rectangle = $\small{\mathfrak{14~cm}}$

➻ Breadth of the rectangle = $\small{\mathfrak{11~cm}}$

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