the length of a rectangle is 3m more than it's width .what are the dimensions if the perimeter is 54m ?
Answers
Answered by
6
Let width be x
length=3+x
2(l+b)=54
2(x+3+x)=54
2x+3=27
2x=24
x=12
width=12 cm
length=15 cm
length=3+x
2(l+b)=54
2(x+3+x)=54
2x+3=27
2x=24
x=12
width=12 cm
length=15 cm
Answered by
5
heya,
______________________________
Let the width of rectangle be x m
So, the length of rectangle be 3+x m
A.T.Q.
2(x+3+x) = 54
=> 2x+6+2x = 54
=> 4x = 54-6
=> 4x = 48
=> x = 48/4
=> x = 12
Therefore,
⚫ Length of rec.
= x m
= 12m
⚫ Width of rec.
= 3+x m
= 3+12m
= 15m
As,
Perimeter of rec.
= 2×(12+15) cm
= 2×27 cm
= 54 cm
______________________________
I hope this answer helps you.....
______________________________
Let the width of rectangle be x m
So, the length of rectangle be 3+x m
A.T.Q.
2(x+3+x) = 54
=> 2x+6+2x = 54
=> 4x = 54-6
=> 4x = 48
=> x = 48/4
=> x = 12
Therefore,
⚫ Length of rec.
= x m
= 12m
⚫ Width of rec.
= 3+x m
= 3+12m
= 15m
As,
Perimeter of rec.
= 2×(12+15) cm
= 2×27 cm
= 54 cm
______________________________
I hope this answer helps you.....
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