Question

The length of a rectangle is( 3x + 2 )cm and it's width is (4x - 3 )cm . Find its area.​

Answer 1

Answer:

11x−3

Step-by-step explanation:

Let's simplify step-by-step.

3x+(2)(4)x−3

=3x+8x+−3

Combine Like Terms:

=3x+8x+−3

=(3x+8x)+(−3)

=11x+−3

=11x-3

PLEASE MARK AS BRAINLIEST

Answer 2

Answer:

${ \huge{ \pmb{ \sf{Required \: Answer...}}}}$

From Question,

Length of Rectangle = 3x + 2cm

Width of rectangle = 4x - 3cm

Finding Area of rectangle:-

${ \boxed{ \sf{Area \: of \: Rectangle = Length × Breadth}}}$

By substituting the values,

${ \implies{ \sf{Area = (3x + 2)(4x - 3)}}}$

${ \implies{ \sf{Area = 12 {x}^{2} - 9x + 8x - 6}}}$

${ \implies{ \sf{Area = 12 {x}^{2} - x - 6}}}$

By Solving the quadratic polynomial,

${ \implies{ \sf{12 {x}^{2} - 9x + 8x - 6 }}}$

${ \implies { \sf{4x(3x + 2) - 3(3x + 2)}}}$

${ \implies{ \sf{(4x - 3)(3x + 2) = 0}}}$

Area of rectangle must be positive,

${ \implies{ \sf{4x - 3 = 0}}}$

${ \implies{ \sf{x = \frac{3}{4} }}}$

Therefore,

Area of Rectangle = 12x² - x - 6 cm² (or) 3/4cm²