Question

The length of a rectangle is 4 cm & the length of its diagonal is 5 cm.The area of the
rectangle is ____​

Answer 1

length of rectangle = 4 cm ( given)

length of diagonal = 5 cm ( given)

Step-by-step explanation:

let the breadth of rectangle = X cm

according to Pythagoras theorem

(4)^2+ (X)^2 = (5)^2

X = (25-16)^1/2

X = 3 cm

then

area of rectangle = length * breadth

= 4* 3 = 12 cm ^2

Answer 2

Given :-

• The length of a rectangle is 4 cm & the length of its diagonal is 5 cm.

To Find :-

• Area of rectangle = ?

Solution :-

• Here, we are given that Length of the rectangle is 4 cm and Length of it's diagonal is 5 cm. and we have to calculate the area of rectangle to calculate area rectangle first we have to find the Breadth of rectangle :]

Let's find the Breadth of rectangle :-

→ Diagonal = √(Length)² + (Breadth)²

→ 5 = √(4)² + (Breadth)²

→ (5)² = (4)² + (Breadth)²

→ 25 = 16 + Breadth²

→ Breadth² = 25 - 16

→ Breadth² = 9

→ Breadth = √9 cm

→ Breadth = 3 cm

Therefore, Breadth of rectangle is 3 cm.

★ According to Question :-

➻ Area of rectangle = Length × Breadth

➻ Area of rectangle = 4 × 3

➻ Area of rectangle = 12 cm²

Therefore,the area of rectangle is 12 cm².

Extra Shots :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²