the length of a rectangle is 4 cm greater than its breadth if its area is96sq cm then uts perimeter is
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Correct question:
The length of rectangle is 4 cm greater than its breadth if it's perimeter is 96 sqcm than its Area?
Given:
Length of the rectangle is 4 cm greater than its breadth
Perimeter rectangle = 96cmsq
Find:
Area of rectangle ?
Solution:
Let the breadth be X
then length = x+4
Perimeter of rectangle = 96sqcm
2(l+b) = 96sqcm
2(x+x+4) = 96sqcm
2x+4 = 96/2
x = 48-4/2
x = 22
Breadth = 22
length = x+4
= 22+4 = 26
length =26
Now Area of rectangle = l×b
= 22 ×26
= 572
Area of rectangle = 572
Verification:
Perimeter of rectangle = 96sqcm
2(l+b) = 96sqcm
2(22+26)= 96sqcm
2×48 = 96sqcm
96sqcm = 96sqcm
Hence verified!
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