Question

the length of a rectangle is 4 cm greater than its breadth if its area is96sq cm then uts perimeter is​

Answer 1

Correct question:

The length of rectangle is 4 cm greater than its breadth if it's perimeter is 96 sqcm than its Area?

Given:

Length of the rectangle is 4 cm greater than its breadth

Perimeter rectangle = 96cmsq

Find:

Area of rectangle ?

Solution:

Let the breadth be X

then length = x+4

Perimeter of rectangle = 96sqcm

2(l+b) = 96sqcm

2(x+x+4) = 96sqcm

2x+4 = 96/2

x = 48-4/2

x = 22

Breadth = 22

length = x+4

= 22+4 = 26

length =26

Now Area of rectangle = l×b

= 22 ×26

= 572

Area of rectangle = 572

Verification:

Perimeter of rectangle = 96sqcm

2(l+b) = 96sqcm

2(22+26)= 96sqcm

2×48 = 96sqcm

96sqcm = 96sqcm

Hence verified!