Question

the length of a rectangle is 4 cm more than the breadth . if the perimeter of rectangle is 80cm find the area of the rectangle​

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Answer 1

Step-by-step explanation:

Let the breadth of the rectangle be x cm.

Then it's length = x+4 cm

Perimeter of the rectangle= 2(l+b)

= 2(x+4+x) = 2(2x+4) = 4x + 8 cm

But perimeter of the rectangle = 40 cm

So. 4x + 8 = 40 => 4x = 40 - 8 => 4x = 32

=> x = 32/4 => x = 8

So breadth = 8 cm

Length of the rectangle = x+4 = 8+4=12 cm

Answer 2

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The area of the rectangle = 396 cm²

Step-by-step explanation:

Solution:

Let,

The breadth of a rectangle = x

The length of a rectangle = x + 4

The perimeter of rectangle = 80 cm (Given)

The perimeter of rectangle = 2 (length +

breadth)

➡ 2 [(x + 4) + x] = 80

→ 2x+8+2x = 80

➡ 4x+8 = 80

→ 4x = 80 - 8

➡ 4x = 72

⇒ x = 72/4

→ x = 18

The breadth of a rectangle = 18 cm

The length of a rectangle = x + 4

→ 18 +4

→ 22

The length of a rectangle = 22 cm

The area of the rectangle = length x breadth

→ 22x 18

→ 396

The area of the rectangle = 396 cm²

Therefore, The area of the rectangle = 396 cm²

hope it was helpful to you