Question

The length of a rectangle is 4 feet more than twice the width. The perimeter is 128 feet. Find the length and width.

Answer 1

l=44ft. and breadth =20 ft

Step-by-step explanation:

refer to an attachment

Answer 2

Answer:

${\pink{\green{\sf{\therefore Length=44\:ft}}}}$

${\pink{\green{\sf{\therefore Breadth=20\:ft}}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

• In the given question information given about relation between length and breath and perimeter is given.

• We have to find sides of this rectangle.

• According to given question :

$\underline \bold{given : } \\ \implies let\:breadth =x\\ \implies length= 2x+4\\ \\ \underline \bold {to \:find :} \\ \implies length = ? \\ \implies breadth = ?$

• Putting values in formula for perimeter of rectangle.

$\implies perimeter \: of \: rectangle = 128 \: ft \\ \implies 2(l + b) = 128 \\ \implies 2( 2x +4+ x) = 128 \\ \implies 3x + 4 = \frac{128}{2} \\ \implies 3x = 64 - 4 \\ \implies x = \frac{60}{3} \\ \bold{\implies x = 20} \\ \\ \bold{\implies breadth =x = 20 \: ft} \\ \bold{\implies length= 2x + 4 = 2 \times 20 + 4 = 44 \: ft}$