The length of a rectangle is 4 m less than 2 times width.If perimeter of the rectangle is 100 m,Find its dimensions
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Answer:
let the breadth of rectangle = xm
then, length=( 2x-4) m
perimeter = 100m
perimeter of rectangle= 2(l+b)
100=2[(2x-4) +x]
100/2= 2x-4+x
50=3x-4
50+4=3x
54=3x
x =54/3
x=18
so, breadth= 18m
and length= 2×18-4
= 36-4
= 32
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