Question

The length of a rectangle is 4 m more than its width. What are the dimensions if the perimeter is 60 m

Answer 1

Answer:

$\large{\underline{\boxed{\sf Length = 17 \: m}}}$

$\large{\underline{\boxed{\sf Width = 13 \: m}}}$

Step-by-step explanation:

Let the width of the rectangle be x. Then, length = (x + 4)m.

According to the question;

Perimeter of rectangle = 60 m

⇒ 2(l + b) = 60

⇒ 2( x + 4 + x) = 60

⇒ 2x + 4 = 60/2

⇒ 2x + 4 = 30

⇒ 2x = 30 - 4

⇒ 2x = 26

⇒ x = $\sf \dfrac{26}{2}$

⇒ x = 13

Thus, dimensions of the rectangle are;

• Length = x + 4 = 13 + 4 = 17 m
• Width = x = 13 m

Hence, the length of the rectangle is 17 m and width is 13m.

Answer 2

let the length = x

and breadth =x+4

aacoroding to question

2(x+x+4)=60

2(2x+4)=60

2x+4=30

2x=26

x=13

so the length wiil be 13 and breadth will be 17

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