Question

the length of a rectangle is 4m more than twice of its breadth.The length and breadth of a rectangle if is perimeter is 140 m,is​

Answer 1

Answer:-

Let the breadth of the rectangle be x m.

Given:

The length is 4 more than twice the breadth.

→ Length of the rectangle = ( 2x + 4 ) m.

And,

Perimeter of the rectangle = 140 m

We know that,

Perimeter of a rectangle = 2 ( length + breadth)

→ 2( 2x + 4 + x ) = 140

→ 2(3x + 4) = 140

→ 6x + 8 = 140

→ 6x = 140 - 8

→ 6x = 132

→ x = 132/6

→ x = 22

→ Breadth (x) = 22 m

→ Length (2x + 4) = 2(22) + 4 = 44 + 4 = 48 m.

Hence, the dimensions of the rectangle are 48 m , 22 m.

Answer 2

Step-by-step explanation:

$\bf Given:-$

• Length of the rectangle is 4m more than its breadth

• The perimeter of the rectangle is 140m

$\bf To\:Find:-$

• The length and breadth of the rectangle.

$\bf Solution:-$

Let the breadth of the rectangle be ' x ' m

Length of the rectangle = (2x + 4)m

As we know that:-

The perimeter of the rectangle is given by the formula

$\boxed{ \sf Perimeter \: of \: the \: rectangle \: = 2(l + b)}$

Substituting the values:-

$\longrightarrow \sf2(2x + 4 + x) = 140$

$\longrightarrow \sf2(3x + 4) = 140$

$\longrightarrow \sf6x + 8 = 140$

$\longrightarrow \sf6x = 140 - 8$

$\longrightarrow \sf6x= 132$

$\longrightarrow \sf x= \dfrac{132}{6}$

$\longrightarrow \sf x= 22$

Therefore:-

Breadth of the rectangle = x = 22m

Length of the rectangle = 2x + 4 = 2(22) + 4 = 48m

Hence;

$\boxed{ \bf Length \: of \: the \: rectangle = 48m}$

$\boxed{ \bf Breadth\: of \: the \: rectangle = 22m}$