Math, asked by daris52, 3 months ago

The length of a rectangle is 5 cm less than twice its breadth . if the perimeter of rectangle is 80 cm , find its area . solve equation by the cross multiplication method.​

Answers

Answered by mathdude500
28

\large\underline{\sf{Solution-}}

Let assume that

↝ Length of a rectangle is 'x' cm

and

↝ Breadth of rectangle is 'y' cm

According to statement,

↝ The length of a rectangle is 5 cm less than twice its breadth.

\rm :\longmapsto\:x = 2y - 5

\bf\implies \:\boxed{ \tt{ \: x - 2y =  -  \: 5 \: }} -  -  - (1)

According to statement again,

↝ The perimeter of rectangle is 80 cm.

\rm :\longmapsto\:2(x + y) = 80

\bf\implies \:\boxed{ \tt{ \: x + y =\: 40 \: }} -  -  - (2)

So, we have two equations as

\rm :\longmapsto\:x + y = 40

and

\rm :\longmapsto\:x - 2y =  - 5

So, using Cross multiplication method, we have

\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf 2 & \bf 3 & \bf 1& \bf 2\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf  1 & \sf 40 & \sf 1 & \sf 1\\ \\ \sf  - 2 & \sf  - 5 & \sf 1 & \sf  - 2\\ \end{array}} \\ \end{gathered}

So,

\red{\rm :\longmapsto\:\dfrac{x}{ - 5  - ( -  80)}  = \dfrac{y}{40 - ( - 5)}  = \dfrac{ - 1}{ - 2 - 1}}

{\rm :\longmapsto\:\dfrac{x}{ - 5 + 80}  = \dfrac{y}{40 + 5}  = \dfrac{ - 1}{ -3}}

{\rm :\longmapsto\:\dfrac{x}{75}  = \dfrac{y}{45}  = \dfrac{1}{3}}

\bf\implies \:x = \dfrac{75}{3}  = 25 \: cm

and

\bf\implies \:y = \dfrac{45}{3}  = 15 \: cm

Hence,

Length of rectangle, x = 25 cm

Breadth of rectangle, y = 15 cm

So,

\boxed{ \tt{ \: Area \: of \: rectangle, A = xy = 25 × 15 =375 \:  {cm}^{2}}}

Answered by Ladylaurel
31

Answer :-

The area of rectangle is 375cm².

Step-by-step explanation

To Find :-

  • The area of rectangle.

Solution :-

Given that,

  • The length of a rectangle is 5 cm less than twice its breadth.
  • The perimeter of rectangle is 80 cm.

ㅤㅤㅤㅤㅤㅤ Assumption

Let us assume the breadth and length of rectangle as (x) cm and (2x - 5) cm .

As we know that,

Perimeter of rectangle = 2(l + b) units.

Where,

  • l = length, b = breadth.

Therefore,

→ 2(length + breadth) = Perimeter of Rectangle

→ 2(2x - 5 + x) = 80

→ 2(3x - 5) = 80

→ 3x - 5 = 80/2

→ 3x - 5 = 40

→ 3x = 40 + 5

→ 3x = 45

→ x = 45/3

→ x = 15

We got, The value of x as 15.

The length and breadth of rectangle is :-

Breadth = (x)cm = 15cm.

Length = (2x - 5)cm = (2*15 - 5) = 30 - 5 = 25cm.

Now, According the question,

The area of rectangle :-

As we know that,

Area of rectangle = lb sq. units

Where,

l = length, b = breadth.

Therefore,

→ lb

→ l*b

→ 15cm*25cm

375cm²

Hence,

The area of rectangle is 375cm².

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