The length of a rectangle is 5 cm less than twice its breadth . if the perimeter of rectangle is 80 cm , find its area . solve equation by the cross multiplication method.
Answers
Let assume that
↝ Length of a rectangle is 'x' cm
and
↝ Breadth of rectangle is 'y' cm
According to statement,
↝ The length of a rectangle is 5 cm less than twice its breadth.
According to statement again,
↝ The perimeter of rectangle is 80 cm.
So, we have two equations as
and
So, using Cross multiplication method, we have
So,
and
Hence,
Length of rectangle, x = 25 cm
Breadth of rectangle, y = 15 cm
So,
Answer :-
The area of rectangle is 375cm².
Step-by-step explanation
To Find :-
- The area of rectangle.
★ Solution :-
Given that,
- The length of a rectangle is 5 cm less than twice its breadth.
- The perimeter of rectangle is 80 cm.
ㅤㅤㅤㅤㅤㅤ Assumption
Let us assume the breadth and length of rectangle as (x) cm and (2x - 5) cm .
As we know that,
Perimeter of rectangle = 2(l + b) units.
Where,
- l = length, b = breadth.
Therefore,
→ 2(length + breadth) = Perimeter of Rectangle
→ 2(2x - 5 + x) = 80
→ 2(3x - 5) = 80
→ 3x - 5 = 80/2
→ 3x - 5 = 40
→ 3x = 40 + 5
→ 3x = 45
→ x = 45/3
→ x = 15
We got, The value of x as 15.
The length and breadth of rectangle is :-
Breadth = (x)cm = 15cm.
Length = (2x - 5)cm = (2*15 - 5) = 30 - 5 = 25cm.
Now, According the question,
The area of rectangle :-
As we know that,
Area of rectangle = lb sq. units
Where,
l = length, b = breadth.
Therefore,
→ lb
→ l*b
→ 15cm*25cm
→ 375cm²
Hence,
The area of rectangle is 375cm².