The length of a rectangle is 5 cm more than its breadth. If the perimeter of the rectangle is 40cm. Find the length and breadth of the rectangle. Answer this question step by step.
Answers
Answer:
ANSWER
Let the shorter side of triangle =x cm
The other side of the triangle =(x+5)cm
The area of reactangle
(x+5)(x)=150
⇒ x
2
+5x−150=0
⇒ (x+15)(x−10)=0
⇒ either x=−15 or x=+10
Since the side cannot be negative
Therefore the value of c=−15 is negligible
When x=10cm, then the other side =10+5=15cm
Explanation:
hope it helps Dr
Given:
The length of a rectangle is 5 cm more than its breadth.
The perimeter of the rectangle is 40 cm.
To be found:
The length and breadth of the rectangle.
So,
let the breath be 'a' cm
So from the question, we get length is 5 cm more than breadth
That means the length is (a+5) cm
The formula to find the perimeter of the rectangle is
= 2(length + breadth) units
So,
⇒ 2[(a+5) + a) = 40
⇒ a + 5 + a = 40 ÷ 2
[Taking 2 to RHS]
⇒ 2a + 5 = 20
⇒ 2a = 20 - 5
[Transporting 5 to RHS]
⇒ 2a = 15
⇒ a = 15 ÷ 2
[Transporting 2 to RHS]
∴ a = 7.5 cm
Thus,
The breadth of the rectangle is = a = 7.5 cm
And the length or the rectangle is = (a+5) = 7.5+5 = 12.5 cm
- - -
Verification:
2(l + b) units
= 2(12.5 + 7.5)
= 2(20)
= 40 cm
Therefore, verified