Question

the length of a rectangle is 5 cm more than its breadth if peimeter is 50 cm find length and breadth.​

Answer 1

Given :-

• The length of a rectangle is 5 cm more than its breadth
• Perimeter is 50 cm

To Find :-

• What is the length and breadth of a rectangle

Formula Used :-

$\bigstar \: \color{magenta} \underline{ \boxed{ \: \bf Perimeter _{(Rectangle)} \: = \: 2( L + B) \: }} \: \color{black} \bigstar$

Where,

• L = Length
• B = Breadth

Solution :-

Let,

• Breadth = x

Given :

• Length = x+5
• Perimeter = 50 cm

According to the question by using formula we get,

$\bf \implies \: Perimeter _{(Rectangle)} \: = \: 2( L + B)$

$\sf \implies \: 50 \: cm \: = \: 2(( x + 5) + (x))$

$\sf \implies \: 50 \: cm \: = \: 2(x + 5+ x)$

$\sf \implies \: 50 \: cm \: = \: 2(2x + 5)$

$\sf \implies \: 50 \: cm \: = \: 4x + 10$

$\sf \implies \: 50 - 10\: = \: 4x$

$\sf \implies \: 40\: = \: 4x$

$\displaystyle\sf \implies \: \cancel\frac{40}{4} \: = \: x$

$\displaystyle\sf \implies \: \frac{10}{1} \: = \: x$

$\displaystyle\sf \implies \: 10\: = \: x$

$\displaystyle\bf \implies \red{\: x \: = \: 10}$

Now,

$\bf⇢ \: Breadth _{(Rectangle)} \: = \: x$

$\bf \red{⇢ \: Breadth _{(Rectangle)} \: = \: 10}$

$\bf⇢ \: Length _{(Rectangle)} \: = \: x + 5$

$\bf⇢ \: Length _{(Rectangle)} \: = \: 10+ 5$

$\bf \red{⇢ \: Length _{(Rectangle)} \: = \: 15}$

∴ Hence, The length and breadth of a rectangle is 15 cm and 10 cm .

$\:$

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Answer 2

$in \: short \: answer$

2 Answers By Expert Tutors

2 Answers By Expert TutorsPerimeter, p=2(x+x-5)=4x-10=50, 4x=60m x=15 (length), breadth is x-5=15-5=10.