Question

the length of a rectangle is 5 cm more than its breadth if the perimeter of the rectangle is 50 cm then what is the area

Answer 1

let breadth of a be x
length of rectangle is 5+x
perimeter =2(5+x+x)
=10+4x
perimeter =50cm
10+4x=50
4x=50-10
4x=40
x=40/4
x=10
length =5+10=15cm
breadth =10cm
area=l*b
=15*10=150 squad cm

Answer 2

The area of the rectangle is 150 square cm.

Given: The length of a rectangle is 5 cm more than its breadth and the perimeter of the rectangle is 50 cm.

To find: We have to find the area of the rectangle.

Solution:

Let the breath of the rectangle be x cm.

The length of a rectangle is 5 cm more than its breadth.

Thus the length of the rectangle is (x+5)cm.

Now the perimeter will be-

$2 \times (x + x + 5)$

The perimeter of the rectangle is 50 cm.

So, we can write-

$2 \times (2x + 5) = 50 \\ 4x + 10 = 50 \\ 4x = 40 \\ x = 10$

Thus breath of the rectangle is 10cm and the length is 15cm.

The area of the rectangle is 10×15=150 square cm.