Question

the length of a rectangle is 5 cm more than its width. The perimeter is 82 cm. Find the length of the rectangle

Answer 1

$\bf \large \it \: Hey \: User!!!$

according to the question, the length of the rectangle is 5cm more than it's breadth.

let the breadth of the rectangle be x. therefore the length of the rectangle is x + 5

perimeter of the rectangle = 82cm
>> 2 ( l + b ) = 82cm
>> 2 ( x + 5 + x ) = 82cm
>> 2x + 5 = 82/2
>> 2x + 5 = 41
>> 2x = 41 - 5
>> 2x = 36
>> x = 36/2
>> x = 18

hence, the breadth of the rectangle is = x = 18m

and the length of the rectangle is = x + 5
= 18 + 5
= 23m

$\bf \large \it{Cheers!!!}$

Answer 2

Hello!

Let :

• $\textbf{Breadth}$ = x
• $\textbf{Length}$ = x + 5

Then,

$\textbf{Perimeter \:of\: rectangle}$ = 82 cm

⇒ 2 ( l + b ) = 82

⇒ ( l + b ) = $\dfrac{\sf 82}{\sf 2}$

⇒ x + x + 5 = 41

⇒ 2x = 36

⇒ x = $\dfrac{\sf 36}{\sf 2}$ = $\boxed{\sf 18 \: cm}$

Therefore,

• Breadth = $\textbf{18\: cm}$
• Length = 18 + 5 = $\textbf{23 \:cm}$

Cheers!