Question

The length of a rectangle is 5 cm more than the width. The area is 24 cm2. Find the length and width.

Answer 1

Answer:

Let the width be x cm

& let the length be (x+5) cm

According to the question,

x(x+5)=24

x2+5x-24=0

x2+8x-3x-24=0

x(x+8)-3(x+8)=0

(x+8)(x-3)=0

x= -8,3

Length=x+5=3+5=8 cm

& Breadth=3 cm

Answer 2

❥${\underline{\underline{\large{\mathtt{ANSWER:-}}}}}$

Length of the rectangle is 8 cm and the width of the rectangle is 3 cm.

❥${\underline{\underline{\large{\mathtt{EXPLANATION:-}}}}}$

•Given:-

• The length of the rectangle is 5 cm more than the width.
• The area of the rectangle is 24 cm².

•To find:-

• Length and width of the rectangle.

•Solution:-

Let the width of the rectangle be X.

So,

the length of the rectangle=(x+5)cm

We know,

$\large{\boxed{\sf{\green{Area\:of\: rectangle=length× width}}}}$

According to the question,

(x+5)x = 24

→x²+5x =24

→x²+5x-24 =0

→x²+(8-3)x-24=0

→x²+8x -3x -24 =0

→x(x+8)-3(x+8)=0

→(x+8)(x-3) = 0

Either,.

x+8=0

→x = -8

Or,

x-3=0

→x = 3

★ Width can't be negative. So the width of rectangle is 3 cm.

Length of rectangle= (3+5) cm

= 8 cm.