The length of a rectangle is 5 cm more than twice its breadth. Find the dimensions of the
rectangle, if its perimeter is 310 cm.
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Let the breadth be x
and the length be 2x+5
Perimeter = 2 ( L + B )
310 = 2 ( 2x+5+x)
310 = 2 (3x+5)
310÷2 = 3x+5
155 = 3x+5
155-5 = 3x
150 = 3x
150÷3 = x
x = 50
Breadth = 50
Length = (2×50) + 5 = 105
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