Question

The length of a rectangle is 5 cm more than twice its width. Find the dimensions (length and width) of the rectangle, if its perimeter is 35 cm​

Answer 1

Answer:

The dimensions of the rectangle are 11.25 cm & 6.25 cm.

Step-by-step-explanation:

Let the length of the rectangle be l cm.

And the breadth of the rectangle be b cm.

From the given condition,

Length = Breadth + 5

⇒ l = b + 5 - - - ( 1 )

Now, we know that,

Perimeter of rectangle = 2 ( Length + Breadth )

⇒ P = 2 ( l + b )

⇒ 35 = 2 ( b + 5 + b ) - - - [ From ( 1 ) ]

⇒ 35 ÷ 2 = 2b + 5

⇒ 2b + 5 = 17.5

⇒ 2b = 17.5 - 5

⇒ 2b = 12.5

⇒ b = 6.25

∴ Breadth = 6.25 cm

By substituting this value in equation ( 1 ), we get,

l = b + 5

⇒ l = 6.25 + 5

⇒ l = 11.25

∴ Length = 11.25 cm

∴ The dimensions of the rectangle are 11.25 cm & 6.25 cm.

Answer 2

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Answer

• Let the length of the rectangle be l cm..
• Let the breadth of the rectangle be b cm..

From the given,

• Length = Breadth + 5
• => l = b + 5 ----> (1)..

Now we know that,

• perimeter of rectangle = 2( l + b)
• 35 = 2 ( b + 5 + b ) ----> from eqn (1)

➜35 ÷ 2 = 2b + 5

➜2b + 5 = 17.5

➜2b = 17.5 - 5

➜2b = 12.5

➜b = 12.5 / 2

➜b = 6.25

(Breadth = 6.25)

• By substituting this value eqn (1),we get

l = b + 5

➜ l = 6.25 + 5

➜ l = 11.25

(Length = 11.25)

The dimensions of rectangle is 11.25cm and 6.25 cm