Question

The length of a rectangle is 5 m less than four times its width. If the perimeter of the rectangle is 180 m, what is its area?​

Answer 1

Answer:

✡1349m²☑

Step-by-step explanation:

Given⤵

• length of rectangle 5m less than four times its width.
• Perimeter of rectangle 180m.

To find⤵

• Area of rectangle.

Solution⤵

⚫Let the width of rectangle is x m.

➡Then length = 4x-5

✡Using formula perimeter of rectangle=2(length+width)

➡180m=2(4x-5+x)

➡180m=2(5x-5)

➡180m=10x-10

➡10x=180+10m

➡x=190/10m

➡x=19m

width=19m

Length=4×19-5=76-5=71m

⚫Using formula area of rectangle= length×width

➡area of rectangle=19×71m²

➡area of rectangle=1349m²

✅Hence, area of rectangle is 1349m².

✍akashbindjnvg ✍

Hope this is helpful to you!

Answer 2

Given :

• Length of a rectangle is 5 m less than four times its width.
• The perimeter of the rectangle is 180 m.

To find :

• its area?

Solution :

⇒ Let's find the length and breadth.

→ Perimeter = 2 (length + breadth)

→ 180m = 2(4x - 5 + x)

→ 180m = 2(5x - 5)

→ 180m = 10x - 10

→ 10x = 180 + 10

→ 10x = 190

→ x = 190/10

→ x = 19 m

∴ x = 19 m

Therefore,

• Breadth = x

= 19 m

• Length = 4x - 5

= 4 × 19 - 5

= 76 - 5

= 71 m

     

⇒ Area of Rectangle = length × breadth

= 71 × 19

= 1349 m²

• Therefore, the length and breadth of the rectangle is 1349 m².

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