Question

the length of a rectangle is 5 M more than its breadth the perimeter of rectangle is 50 m? what will be the length and breadth of rectangle

Answer 1

let the breadth of rectangle be x and then length will be x+5 

perimeter of rectangle = 2(l+b)

here, 50 =2(x+x+5)

50/2 = 2x+5

25=2x+5

25-5=2x

20=2x

20/2 = x

10= x

then the breadth of rectangle is 10 m and length is 10+5=15m

Answer 2

hiii!!!

here's ur answer...

given that the length of the rectangle is 5m more than it's breadth.

let the breadth of the rectangle be x, therefore length of the rectangle will be = x + 5

perimeter of the rectangle = 50m

==> 2 ( L + B ) = 50m

==> 2 ( x + 5 + x ) = 50m

==> 2 ( 2x + 5 ) = 50m

==> 4x + 10 = 50m

==> 4x = 50 - 10

==> 4x = 40m

==> x = 40/4

==> x = 10m

hence, breadth of the rectangle = x

= 10m

length of the rectangle = x + 5

= 10 + 5

= 15m

VERIFICATION:-

perimeter of the rectangle = 2 ( l + b )

= 2 ( 15 + 10 )

= 2 × 25

= 50m

hence verified

hope this helps u..!