The length of a rectangle is 5 meter longer than twice the breadth. If the perimeter of the rectangle is 310 meter found the length the length of the rectangle
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Answer:
Let the breadth be x
then length=2x+5
a/q
(x+2x+5)2=310
(3x+5)2=310
6x+10=310
6x=310-10
6x=300
x=300÷6
x=50
breadth=50 metre
length=2×50+5=100+5=105metre
Answered by
0
Answer:
length is 105
let breadth be x
then, length will 2x + 5 (5 meter longerthan twice the breadth)
perimeter = 310
then formula of perimeter of rectancle is 2 (l+b)
so,
2(x +2x +5) = 310
2x + 4x + 10 = 310
6x + 10 = 310
6x = 310 - 10
6x = 300
x = 300/6
x = 50
breadth = 50
length = 2x + 5
2 × 50 + 5
100 + 5
105
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