Question

the length of a rectangle is 5 meters less than twice the breadth.if the perimeter is 50 metres ,find the length and breadth of the rectangle. ​

Answer 1

Answer:

32 cm is the correct answer

Step-by-step explanation:

Answer

Let the breadth of the original rectangle be xcm

Then , length of the original rectangle will be (2x−5)cm

If the length is decreased by 3cm , then ,

New length ={(2x−5)−3}

=(2x−8)cm

If breadth is increased by 2cm , then ,

New breadth =(x+2)cm

New perimeter =2 (new length + new breadth)

=2{(2x−8)+(x+2)}

=2(2x−8+x+2)

=2(3x−6)

We get ,

=6x−12

According to the given problem ,

6x−12=72

6x=72+12

6x=84

x=

6

84

We get ,

x=14

Breadth of the original rectangle =14 cm and

Length of the original rectangle =(2x−5)

=2×14−5

=28−5

=23cm

Area of original rectangle = Length × Breadth

=(23×14)cm

2

=322cm

2

Therefore , area of the original rectangle is 322cm

2

Answer 2

Given that perimeter=50meters

Let's take breadth =X

length=2x-5

perimeter of a rectangle=2(l + b)

50=2(2x -5+ X)

,50= 4x-10+2x

50= 6x -10

50+10= 6x

60=6x

60/6=X

X=10

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