Question

the length of a rectangle is 5 metre greater than its breadth and its perimeter is 250 m find the length and breadth​

Answer 1

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★Assume Breadth be p

★So length will be (p + 5)

★Perimeter = 250

$\fbox{Perimeter of rectangle = 2(length + breadth)}$

250 = 2(p + p + 5)

250 = 2(2p + 5)

250 = 4p + 10

250 - 10 = 4p

240 = 4p

${\boxed{\sf\:{p=\dfrac{240}{4}}}}$

p = 60

${\boxed{\sf\:{Breadth=60}}}$

★Now we have to find length and we have :-

${\boxed{\sf\:{Length=p+5}}}$

= (60) + 5

= 65

$\Large{\boxed{\sf\:{Length=65\;and\; Breadth=60}}}$

Answer 2

Answer:

: Solution :

Suppose the Breadth = x .

and the length = x + 5 .

Perimeter = 250 m

Formula to find the length of a rectangle :

2(Length + Breadth )

250 = 2( x + x + 5 )

250 = 2( 2x + 5 )

250 = 4x + 10

250 - 10 = 4x

240 = 4x

x = 240/4

x = 60

Length = x + 5

= 60 + 5

= 65

The Breadth of Rectangle = 60.

The length of Rectangle = 65 .