The length of a rectangle is 5 metre more 5 times of its breadth the area of rectangle is 2010 sq meters find the perimeter of rectangle
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Let the shorter side of triangle =x cm
The other side of the triangle =(x+5)cm
The area of reactangle
(x+5)(x)=150
⇒ x
2
+5x−150=0
⇒ (x+15)(x−10)=0
⇒ either x=−15 or x=+10
Since the side cannot be negative
Therefore the value of c=−15 is negligible
When x=10cm, then the other side =10+5=15cm
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