Question

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50
metres, find the length and breadth of the rectangle.
Ir
Let the breadth be x
sided po
Then length
Perimeter = 50 metres
Length + breadth
+ x = 25
3x -
= 25
3x =
X =
metres
metres, length =
breadth =​

Answer 1

${Solution}$

Appropriate Question:-

The length of rectangle is 5 meters less tgan than twice of breadth .Perimeter of rectangle is 50 m .Find the length and breadth of rectangle

SOLUTION:-

As they given ,

Length is 5 meters less than twice of breadth

Let the breadth of rectangle is x

then length will be According to statement

• L = 2x - 5
• B = x

Perimeter of recatngle is 50m

As we know that ,

Perimeter of rectangle = 2(l + b)

50= 2( 2x -5 + x)

50 = 2 (3x -5)

50 = 6x - 10

50 + 10 = 6x

60 = 6x

x = 60/6

x = 10

So, breadth of rectangle is 10m

Length = 2x -5

= 2(10) -5

= 20-5

= 15

Length of rectangle is 15m

So, the required dimensions of rectangle i.e length and breadth is 15m and 10m

__________________

Know more :-

• Perimeter of square is 4a
• Perimeter of rhombus is 4a
• Perimeter of Equilateral triangle is 3a
• Perimeter of Scalene triangle is a + b + c
• Perimeter of pentagon is 5a
• Perimeter of hexagon is 6a
• Perimeter of parallelogram is 2( a +b)

Here 'a' represents side

Answer 2

$\Large{\bf{\green{\mathfrak{\dag{\underline{\underline{Given:-}}}}}}}$

• The length of a rectangle is 5 metres less than twice the breadth. Perimeter of the rectangle is 50 m.

$\Large{\bf{\orange{\mathfrak{\dag{\underline{\underline{To \: Find:-}}}}}}}$

• Length and Breadth of the rectangle

$\Large{\bf{\red{\mathfrak{\dag{\underline{\underline{Solution:-}}}}}}}$

First,

• Let

• Breadth be b

• Length be l

According to the question,

• Breadth = b

Length is 5 meters less than twice the breadth.

This implies that,

• Length = 2b - 5

And

• Perimeter of the rectangle is 50 m.

We know that,

$\boxed{\pink{\sf Perimeter \: of \: rectangle \: = \: 2 \: (l \: + \: b)}}$

• Here,

• l = 2b - 5

• b = b

Perimeter of Rectangle = 50

Substituting the values,

• $\sf 50 \: = \: 2 \: (2b \: - \: 5 \: + \: b)$

• $\sf 50 \: = \: 2 \: (3b \: - \: 5)$

• $\sf 50\: = \: 6b \: - \: 10$

• $\sf 50 \: + \: 10 \: = \: 6b$

• $\sf 60 \: = \: 6b$

• $\sf b \: = \: \dfrac{60}{6}$

• $\sf b \: = \: \cancel{\dfrac{60}{6}}$

• b = 10 m

Then,

• l = 2b - 5

Substituting the value,

• l = 2 * 10 - 5

• l = 20 - 5

• l = 15 m

Therefore,

$\bullet{\leadsto} \: \underline{\boxed{\purple{\texttt{Length and Breadth of the rectangle = 15m and 10m.}}}}$

$\Large{\bf{\green{\mathfrak{\dag{\underline{\underline{Formulas \: Used:-}}}}}}}$

$\sf Perimeter \: of \: rectangle \: = \: 2 \: (l \: + \: b)$

• where,

• l is length of the rectangle

• b is the breadth of the rectangle