Question

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 metres, find the length and breadth of the triangle

Answer 1

Answer:

Let the breadth of the original rectangle be xcm

Then , length of the original rectangle will be (2x−5)cm

If the length is decreased by 3cm , then ,

New length ={(2x−5)−3}

=(2x−8)cm

If breadth is increased by 2cm , then ,

New breadth =(x+2)cm

New perimeter =2 (new length + new breadth)

=2{(2x−8)+(x+2)}

=2(2x−8+x+2)

=2(3x−6)

We get ,

=6x−12

According to the given problem ,

6x−12=72

6x=72+12

6x=84

x=

6

84

We get ,

x=14

Breadth of the original rectangle =14 cm and

Length of the original rectangle =(2x−5)

=2×14−5

=28−5

=23cm

Area of original rectangle = Length × Breadth

=(23×14)cm

2

=322cm

2

Therefore , area of the original rectangle is 322cm

2