The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 metres, find length and breadth of the rectangle
Answers
Step-by-step explanation:
Let the breadth of the rectangle be x meter.
The length of a rectangle is 5 meters less than twice the breadth. So, twice the breadth is 2*x = 2x, and 5 meters less than twice the breadth is 2x-5.
Therefore, the length of the rectangle = (2x-5)m
Formula for perimeter of a rectangle = 2(l + b)
Perimeter of the rectangle = 50m = 2(l +b)
Therefore,
2(l + b) = 2(2x-5 + x) {Substituting the values of l and b}
=50 = 2(3x-5) = 6x-10
=6x = 50 + 10 = 60
=x = 60/6 = 10m
Therefore,
Breadth = x = 10m
Length = 2x-5 = 2*10-5 = 20-5 = 15m
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ℑ ࿐
The length of a rectangle is 5 metres less than twice the breadth. Perimeter of the rectangle is 50 m.
Length and Breadth of the rectangle
First,
Let
Breadth be b
Length be l
According to the question,
Breadth = b
Length is 5 meters less than twice the breadth.
This implies that,
Length = 2b - 5
And
Perimeter of the rectangle is 50 m.
We know that,
Here,
l = 2b - 5
b = b
Perimeter of Rectangle = 50
Substituting the values,
b = 10 m
Then,
l = 2b - 5
Substituting the value,
l = 2 * 10 - 5
l = 20 - 5
l = 15 m
Therefore,
- where,
l is length of the rectangle
b is the breadth of the rectangle