Math, asked by Anonymous, 2 months ago

the length of a rectangle is 5 metres less than twise the breadth. If the perimeter is50 metres, find the length and breadth of the rectangle​

Answers

Answered by amitadwivedi391
1

Answer:

Let the breadth be x

So , length is 2x - 5

Perimeter = 50

So,

2(x + 2x -5) = 50

2x + 4x -10 = 50

6x - 10 = 50

6x = 60

x = 60/6 = 10

Breadth = 10 metres

Length = 15 metres

Hope this helps you !!!!!

Answered by Anonymous
52

Answer:

  • The Length and breadth are 15cm and 10cm respectively

Step-by-step explanation:

Given:

  • the length of a rectangle is 5 metres less than twice the breadth
  • the perimeter of the rectangle is 50 metres

To Find:

  • find the length and breadth of the rectangle​

Assumptions:

  • Let the breadth of the rectangle be x
  • Let the length of the rectangle be 2x - 5

Solution:

Since we know that,

\qquad \qquad \dag \bigg[\bf Perimeter = 2( L + B )\bigg]

According to the question,

\rightarrow \qquad \tt 50 = 2( 2x - 5 + x )

\rightarrow \qquad \tt 50 = 4x - 10 + 2x

\rightarrow \qquad \tt 50 = 6x - 10

\rightarrow \qquad \tt 6x = 50 + 10

\rightarrow \qquad \tt 6x =60

\rightarrow \qquad \tt x = \cancel\dfrac{60}{10}

\rightarrow \qquad {\purple{\underline{\boxed{\frak{ x = 10 }}}\bigstar}}

Now let's find the dimensions,

\nrightarrow \qquad \sf Length = 2x - 5 = 2( 10 ) - 5 = 15cm

\nrightarrow \qquad \sf Breadth = 1x = 1(10) = 10cm

Therefore:

  • The dimensions of the rectangle are 15cm and 10cm

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