Question

The length of a rectangle is 5 more than the width what are the dimensions of the rectangle if the perimeter is 34?​

Answer 1

Answer:

In order to find the area or sq. footage we have to know the length and width which we will know when we find the value of X. To find X we are going to establish a formula, here it is:

(X+5)+(X+5)+X+X=34 , we know the length is 5 feet longer than than the width and all four sides' will have a perimeter of 34 feet. Next we break the formula down:

4X+10=34

4X+10–10=34–10

4X=24 , 4 will go into itself once and 4 will go into 24 six times, hence:

X=6

Now lets prove X is 6:

(6+5)+(6+5)+6+6=34

11+11+12=34

Its area or sq. ft. is going to be 11×6 which equals 66 sq. ft. So 66 sq. ft. is our answer

Step-by-step explanation:

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Answer 2

Answer:

this is is your ans ok byby in short ans

Step-by-step explanation:

Let length of the rectangle be denoted by l and width by w . Now according to the question, the length is 5 more than the width. So, l=5w and perimeter of the rectangle is given to be 22feet . Hence, the length of the rectangle is 110inches and the width of the rectangle is 22inches .