Question

The length of a rectangle is 5 times its width. If the perimeter of the rectangle is 72 cm, then what is the area of the rectangle?​

Answer 1

Topic

Perimeter and Area

Given

• Length of a rectangle is 5 times its width.

• Perimeter of rectangle is 72 cm.

To Find

Area of the rectangle.

Formula to be Used

Rectangle's

• Perimeter = 2( L + B )

• Area = L × B

where

• L = Length

• B = Breadth / Width

Solving

It is given that length of a rectangle is 5 times its width.

L = 5 × B

It is given that perimeter of that rectangle is

72cm.

Perimeter = 2( L + B )

72 cm = 2( L + B )

72 cm = 2( 5B + B )

72 cm = 2 × 6B

72 cm = 12B

72 cm / 12 = B

6 cm = B

So, width of given rectangle is 6 cm.

And

L = 5 × B

L = 5 × 6 cm

L = 30 cm

Length of given rectangle is 30 cm.

Now,

Area = Length × Breadth

Area = 30 cm × 5 cm

Area = 150 cm²

Answer

So, the area of given rectangle is 150 cm².

Learn More :-

Rectangle

It is a quadrilateral.

It is a parallelogram.

Its diagonals are equal in length.

Opposite Sides are equal in length.

Answer 2

given:

length of rectangle is 5 times of its width

perimeter of rectangle is 72 cm

to find:

area of rectangle

solution-

by the question,

perimeter of rectangle = 2 ( length + breadth )

72 cm = 2 ( 5b +b)

72 cm = 2 × 6b

72 cm = 12b

72cm/12 = b

6cm = b

so, breadth of given rectangle is 6m

and

l = 5 × b

l = 5 × 6cm

l = 30cm

length of the given rectangle is 30 cm

now ,

area = lenght × breadth

= 30 cm × 5 cm

= 150 cm^2

therefore ,the area of given rectangle is 150cm^2