Question

The length of a rectangle is 5cm more than its breadth . If the perimeter and f the rectangle is 50cm the what is thera​

Answer 1

Step-by-step explanation:

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Answer 2

AnswEr :

150 cm².

$\bf{\purple{\underline{\underline{\bf{Given\::}}}}}$

The length of a rectangle is 5 cm more than it's breadth. If the perimeter of the rectangle is 50 cm.

$\bf{\purple{\underline{\underline{\bf{To\:find\::}}}}}$

The area of rectangle.

$\bf{\purple{\underline{\underline{\bf{Explanation\::}}}}}$

Formula use :

$\bf{\boxed{\sf{Perimeter\:of\:rectangle\:=2(Length+breadth)}}}}}}$

$\bf{We\:have}\begin{cases}\sf{Length\:(l)=(r+5)\:cm}\\ \sf{Breadth\:(b)=r \:m}\\ \sf{Perimeter\:of\:rectangle\:=\:50\:cm}\end{cases}}$

A/q

$\mapsto\sf{2(l+b)=50}\\\\\\\mapsto\sf{2\big[(r+5)+(r)\big]=50}\\\\\\\mapsto\sf{2(2r+5)=50}\\\\\\\mapsto\sf{4r+10=50}\\\\\\\mapsto\sf{4r=50-10}\\\\\\\mapsto\sf{4r=40}\\\\\\\mapsto\sf{r=\cancel{\dfrac{40}{4} }}\\\\\\\mapsto\sf{\red{r=10\:cm}}$

So,

$\bullet\:\:\sf{Length\:of\:rectangle\:=\:(10+5)cm=15\:cm}\\\bullet\:\sf{Breadth\:of\:rectangle\:=\:r=10\:cm}}$

__________________________________________

$\blacksquare\bf{\underline{\underline{\tt{Area\:of\:rectangle\::}}}}}$

$\hookrightarrow\sf{Area\:=\:Length \times breadth}\\\\\\\hookrightarrow\sf{Area\:=\:15\:cm \times 10 cm}\\\\\\\hookrightarrow\sf{\red{Area\:=\:150\:cm^{2} }}$