The length of a rectangle is 5cm more than its breadth. If the length is decreased by 3 cm and breadth is decreased by 2 cm, then area of the new rectangle is same as the area of the original rectangle. Find the dimensions of the original rectangle.
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Answer:
Let the breadth of the original rectangle be xcm
Then , length of the original rectangle will be (2x−5)cm
If the length is decreased by 3cm , then ,
New length ={(2x−5)−3}
=(2x−8)cm
If breadth is increased by 2cm , then ,
New breadth =(x+2)cm
New perimeter =2 (new length + new breadth)
=2{(2x−8)+(x+2)}
=2(2x−8+x+2)
=2(3x−6)
We get ,
=6x−12
According to the given problem ,
6x−12=72
6x=72+12
6x=84
x=
6
84
We get ,
x=14
Breadth of the original rectangle =14 cm and
Length of the original rectangle =(2x−5)
=2×14−5
=28−5
=23cm
Area of original rectangle = Length × Breadth
=(23×14)cm
2
=322cm
2
Therefore , area of the original rectangle is 322cm
2
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