Math, asked by something01, 2 months ago

The length of a rectangle is 5cm more than its breadth. If the length is decreased by 3 cm and breadth is decreased by 2 cm, then area of the new rectangle is same as the area of the original rectangle. Find the dimensions of the original rectangle.
Plz give proper answer Im struggling from when
will mark as brainliest only if answer is proper

Answers

Answered by Anonymous
1

Answer:

Let the breadth of the original rectangle be xcm

Then , length of the original rectangle will be (2x−5)cm

If the length is decreased by 3cm , then ,

New length ={(2x−5)−3}

=(2x−8)cm

If breadth is increased by 2cm , then ,

New breadth =(x+2)cm

New perimeter =2 (new length + new breadth)

=2{(2x−8)+(x+2)}

=2(2x−8+x+2)

=2(3x−6)

We get ,

=6x−12

According to the given problem ,

6x−12=72

6x=72+12

6x=84

x=

6

84

We get ,

x=14

Breadth of the original rectangle =14 cm and

Length of the original rectangle =(2x−5)

=2×14−5

=28−5

=23cm

Area of original rectangle = Length × Breadth

=(23×14)cm

2

=322cm

2

Therefore , area of the original rectangle is 322cm

2

Similar questions