Math, asked by ansafca4487, 11 months ago

The length of a rectangle is 5m greater than its breadth and its perimeter is 244m find its length and breadth

Answers

Answered by RvChaudharY50
69

\Large\underline{\underline{\sf{Given}:}}

  • length of a rectangle is 5m greater than its breadth.
  • Perimeter of Rectangle = 244m.

\large\star{\underline{\tt{\red{To\:Find}}}}\star

  • length and breadth of Rectangle ?

\Large\bold\star\underline{\underline\textbf{Formula\:used}}

  • Perimeter of Rectangle = 2(Length + Breadth ).

\large\star{\underline{\tt{\red{Answer}}}}\star

Let Breadth of Rectangle be x m.

→ Than Length = (x + 5)m.

So,

→ Perimeter = 2(l+b)

→ 244 = 2(x + 5 + x )

→ 244 = 2(2x + 5)

→ 244 = 4x + 10

→ 244 - 10 = 4x

→ 4x = 234

→ x = 58.5m.

So,

Length = 58.5 + 5 = 63.5m.

\underline\textbf{Hence, Length  \& Breadth of Rectangle}\\ \underline\textbf{are  \red{58.5m} \&  \red{63.5m} Respectively.}

\rule{200}{4}

\bf\red\bigstar\underline\textbf{\blue{Extra}\:Brainly\: \pink{Knowledge}}\red\bigstar

1) Each of the interior angles of a rectangle is 90°.

2) The diagonals of a rectangle bisect each other.

3) The opposite sides of a rectangle are parallel.

4) The opposite sides of a rectangle are equal.

5) A rectangle whose side lengths are a and b has area = a×b×sin90° = a×b

6) A rectangle whose side lengths are a a and b b has perimeter 2(a + b)...

7) The length of each diagonal of a rectangle whose side lengths are a and b is √(a²+b²)..

\rule{200}{4}

\huge\bold{\red{\ddot{\smile}}} \:

Answered by vikram991
30

\huge{\bf{\underline{\red{Solution:}}}}

Given,

  • The length of rectangle is 5 m more than its breadth
  • Perimeter of Rectangle = 244 m

To Find,

  • Length = ?
  • Breadth = ?

Solution,

Suppose the breadth of Rectangle be x

So, the length be (x +5)\

We know that :

\boxed{\bold{\star{\red{Perimeter \ of \ Rectangle = 2(length + Breadth)}}}}

According to Question :-

\implies \bold{2( x + x + 5) = 244 }

\implies \bold{2(2x + 5) = 244}

\implies \bold{ 4x + 10 = 244}

\implies \bold{4x = 244 - 10}

\implies \bold{4x = 234}

\implies \bold{x = \frac{234}{4}}

\implies \boxed{\bold{\red{x = 58.5 m}}}

Now Breadth (x + 5) = 58.5 + 5 = 63.5 m

Length = 58.5 m And Breadth = 63.5 m

\rule{200}2

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