Question

the length of a rectangle is 5meters less than twice the breadth. if the perimeter is 50 metres, find the length and breadth of a rectangle.​

Answer 1

Answer:

Let the breadth of the rectangle be x m.

Then, the length of the rectangle is (2x-5) m.

Perimeter of the rectangle = 50 m

2( L + B ) = 50

2 [(2x-5) + x] = 50

(2x-5) + x = 25

2x - 5 + x = 25

3x = 30

x = 10 m

(2x-5) = 15m

So, the breadth and length of the rectangle are 10 m an 15 m respectively.

I hope this helps.

Answer 2

Given :-

The  length of a rectangle is 5meters less than twice the breadth. if the perimeter is 50 metres

To Find :-

Length

Breadth

Solution :-

Let the breadth be x

Length = 2x - 5

Perimeter = 2(l + b)

50 = 2(2x - 5 + x)

50/2 = 2x - 5 + x

25 = 3x - 5

25 + 5 = 3x

30 = 3x

30/3 = x

10 = x

Breadth = 10 m

Length = 2(10) - 5 = 15 m

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