Question

. The length of a rectangle is 6 cm, and the width is 4 cm. If the length is increased by 2
cm, what should the width be so that the new rectangle has the same area as the first
one?

Answer 1

Question:

The length of a rectangle is 6 cm, and the width is 4 cm. If the length is increased by 2cm, what should the width be so that the new rectangle has the same area as the first one?

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Given :

• Length of rectangle = 6cm
• Breadth of rectangle = 4cm
• Length of new rectangle = 6+2 = 8cm
• Area of rectangle = Area of new rectangle

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To find :

• Width of new rectangle.

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Solution:

Area of rectangle :

$\boxed {\boxed {\bf Area_(rectangle) = length \times breadth }}$

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Area of rectangle one :

$: \implies \sf { Area = 6 \times 4 }$

$: \implies \sf { Area = 24 cm^2 }$

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Area of rectangle one = area of new rectangle

$: \implies \sf { 24 = 8 \times breadth }$

$: \implies \sf { Breadth \: of \: new \: rectangle = 3cm}$

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Answer 2

Question:

The length of a rectangle is 6 cm, and the width is 4 cm. If the length is increased by 2cm, what should the width be so that the new rectangle has the same area as the first one?

ㅤㅤㅤㅤㅤ

Given :

Length of rectangle = 6cm

Breadth of rectangle = 4cm

Length of new rectangle = 6+2 = 8cm

Area of rectangle = Area of new rectangle

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To find :

Width of new rectangle.

Solution

Area of rectangle)=length×breadth

Area of rectangle one :

⟹Area=24cm ㅤㅤㅤㅤ

Area of rectangle one = area of new rectangle

⟹24=8×breadth

⟹Breadth of new rectangle=3cm